Answer
$\log_{7} 6+\log_{7} 2-\log_{7} 5$
Work Step by Step
Step 1: $\log_{7} \frac{6\cdot2}{5}$
Step 2: $\log_{7} (6\times2)-\log_{7} 5$
Step 3: $\log_{7} 6+\log_{7} 2-\log_{7} 5$
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