Answer
$x=\dfrac{1}{2}$
Work Step by Step
$\log_{49}7=x$
Rewrite in exponential form:
$49^{x}=7$
Rewrite $49$ as $7^{2}$:
$(7^{2})^{x}=7$
Multiply the exponents on the left side of the equation:
$7^{2x}=7$
If $7^{2x}=7$, then $2x=1$:
$2x=1$
Solve for $x$:
$x=\dfrac{1}{2}$
