Chapter 12 - Section 12.5 - Logarithmic Functions - Exercise Set - Page 876: 99

.0827

$\log {(1-k)} = -.3/H$ $H=8$ $\log {(1-k)} = -.3/H$ $\log {(1-k)} = -.3/8$ $\log {(1-k)} = -.0375$ We can rewrite the equation as follows: $10^{-.0375} =1-k$ $.917276 = 1-k$ $.917276+k-.917276=1-k+k-.917276$ $k = .082724$ $k=.0827$