Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.5 - Logarithmic Functions - Exercise Set - Page 876: 96

Answer

Please see the graph.

Work Step by Step

Blue line: $y=\log_{1/2}x$ Green line: $y=(1/2)^{x}$ $y=\log_{1/2}x$ $x=2$ $y=\log_{1/2}x$ $y=\log_{1/2}2$ $-1=\log_{1/2}2$ $(2,-1)$ $x=4$ $y=\log_{1/2}x$ $y=\log_{1/2}3$ $-2=\log_{1/2}3$ $(4,-2)$ $x=8$ $y=\log_{1/2}x$ $y=\log_{1/2}9$ $-3=\log_{1/2}9$ $(8,-3)$ $y=(1/2)^{x}$ $x=-3$ $y=(1/2)^{x}$ $y=(1/2)^{-3}$ $8=(1/2)^{-3}$ $(-3,8)$ $x=-2$ $y=(1/2)^{x}$ $y=(1/2)^{-2}$ $4=(1/2)^{-2}$ $(-2,4)$ $x=-1$ $y=(1/2)^{x}$ $y=(1/2)^{-1}$ $2=(1/2)^{-1}$ $(-1, 2)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.