Answer
2.3
Work Step by Step
pH = $-\log {(H^+)}$
$H^+ = .005$
pH = $-\log {(H^+)}$
pH = $-\log {(.005)}$
We can rewrite the equation as follows:
$10^{-pH} = .005$
$pH = 2.3$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 12 - Section 12.5 - Logarithmic Functions - Exercise Set - Page 876: 100
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
