Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.5 - Logarithmic Functions - Exercise Set: 56

Answer

$x=3$

Work Step by Step

We know that if $b\gt0$ and $b\ne1$, then $y=log_{b}x$ is equivalent to $x=b^{y}$ (where $x\gt0$ and $y$ is a real number). Therefore, $log_{9}x=\frac{1}{2}$ is equivalent to $9^{\frac{1}{2}}=x$. Therefore, $x=3$, because $9^{\frac{1}{2}}=\sqrt 9=3$.
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