Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.5 - Logarithmic Functions - Exercise Set - Page 875: 53

Answer

$x=-3$

Work Step by Step

We know that if $b\gt0$ and $b\ne1$, then $y=log_{b}x$ is equivalent to $x=b^{y}$ (where $x\gt0$ and $y$ is a real number). Therefore, $log_{3}\frac{1}{27}=x$ is equivalent to $3^{x}=\frac{1}{27}$. Therefore, $x=-3$, because $3^{-3}=\frac{1}{3^{3}}=\frac{1}{27}$.
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