Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.3 - Exponential Functions - Exercise Set - Page 863: 57

Answer

$C$

Work Step by Step

Given $f(x)=(\frac{1}{2})^x$ it can be seen that $f(1)=(\frac{1}{2})^1=\dfrac{1}{2}$, this means that the point $(1,\frac{1}{2})$ has to be in the graph of $f$, which is in the graph of $C$.
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