Answer
No, it is not a one-to-one function.
Work Step by Step
If we look at all the outputs, we notice that there is a repeated output(3). Therefore, the function is not one-to-one because not all inputs have unique outputs.
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 12 - Section 12.2 - Inverse Functions - Exercise Set - Page 850: 8
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