Answer
$(g\circ h)(0)=0$
Work Step by Step
$g(x)=-2x;$ $h(x)=\sqrt{x}$
$(g\circ h)(0)$
First, find $h(0)$ by substituting $x$ by $0$ in $h(x)$:
$h(0)=\sqrt{0}=0$
Find $(g\circ h)(0)$ by substituting $x$ with $0$ in $g(x)$:
$(g\circ h)(0)=g(0)=-2(0)=0$
