Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Review - Page 906: 56

Answer

$\log_{2} 18$

Work Step by Step

$\log_{2} 6+\log_{2} 3=\log_{2} (6\times3)=\log_{2} 18$
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