Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Review: 43

Answer

{$\frac{1}{64}$}

Work Step by Step

Using logarithmic principles, $\log_{4} x=-3$ can be changed to $x=4^{-3}$. Solving further, $x=4^{-3}=\frac{1}{4^{3}}=\frac{1}{64}$ Therefore, the solution set is {$\frac{1}{64}$}.
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