Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Review - Page 906: 41

Answer

$16=(\frac{1}{2})^{-4}$

Work Step by Step

Since $\log_{x} b=a$ can be written as $b=x^{a}$, $\log_{\frac{1}{2}} 16=-4$ can be written as $16=(\frac{1}{2})^{-4}$.
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