Answer
$f^{-1}(x)=\frac{x-1}{2}$
Work Step by Step
Equation given:
$f(x) = 2x+1$
Replace $f(x)$ with $y$:
$y = 2x+1$
Make x the subject:
$\frac{y-1}{2} = x$
Interchange x and y:
$\frac{x-1}{2} = y$
Thus the inverse function is:
$f^{-1}(x)=\frac{x-1}{2}$