Answer
$(f \circ g)(-1) = -2$
Work Step by Step
Functions involved:
$f(x)=x^2-2$
$g(x) = x+1$
Substitute $g(x)$ into $f(x)$:
$(f \circ g)(x) = (x+1)^2-2$
Substitute $-1$ into $(f \circ g)(x)$:
$(f \circ g)(-1) = (-1+1)^2-2$
$(f \circ g)(-1) = (0)^2-2$
$(f \circ g)(-1) = -2$
