Answer
$(h \circ h)(2)=48$
Work Step by Step
Functions involved:
$h(x)=x^3-x^2$
Substitute $h(x)$ into $h(x)$:
$(h \circ h)(x)=(x^3-x^2)^3-(x^3-x^2)^2$
Substitute $2$ into $(h \circ h)(x)$:
$(h \circ h)(2)=((2)^3-(2)^2)^3-((2)^3-(2)^2)^2$
$(h \circ h)(2)=(8-4)^3-(8-4)^2$
$(h \circ h)(2)=4^3-4^2$
$(h \circ h)(2)=64-16 =48$
