Answer
$2-x$
Work Step by Step
$\frac{x^{2}-4x+4}{2-x}$
=$\frac{x^{2}-2x-2x+4}{-x+2}$
=$\frac{x(x-2)-2(x-2)}{-1(x-2)}$
=$\frac{(x-2)(x-2)}{-1(x-2)}$
=$\frac{(x-2)}{-1}$
=$-(x-2)$
=$-x+2$
=$2-x$
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