Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Cumulative Review: 16

Answer

$\frac{1}{4}x^{2}-9$

Work Step by Step

$(\frac{1}{2}x+3)(\frac{1}{2}x-3)$ =$\frac{1}{2}x(\frac{1}{2}x-3)+3(\frac{1}{2}x-3)$ =$\frac{1}{4}x^{2}-\frac{3}{2}x+\frac{3}{2}x-9$ =$\frac{1}{4}x^{2}-9$
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