Answer
$\frac{1}{4}x^{2}-9$
Work Step by Step
$(\frac{1}{2}x+3)(\frac{1}{2}x-3)$
=$\frac{1}{2}x(\frac{1}{2}x-3)+3(\frac{1}{2}x-3)$
=$\frac{1}{4}x^{2}-\frac{3}{2}x+\frac{3}{2}x-9$
=$\frac{1}{4}x^{2}-9$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 12 - Cumulative Review - Page 912: 16
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