Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Test: 10

Answer

x = 7 or x=6

Work Step by Step

$(x+1)^{2}$ - 15(x+1) + 56 = 0 Substitute y = x+1 $y^{2}$ - 15y +56 = 0 (y-8)(y-7) = 0 y = 8 or 7 Since x+1 = 8 or x+1 = 7 x = 7 or 6
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