Answer
$(3,0)$
Work Step by Step
$f(x)=(x-3)^2$
$(x-3)^2=(x-3)(x-3)$
$(x-3)^2=x^2-6x+9$
$a=1$, $b=-6$, $c=9$
Vertex: $x=-b/2a$
$x=-(-6)/2*1$
$x=6/2$
$x=3$
$f(x)=(x-3)^2$
$f(3)=(3-3)^2$
$f(3)=0^2$
$f(3)=0$
$(3,0)$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.