Answer
$y=-1/2±\sqrt {5/16}$
Work Step by Step
$16y^2+16y=1$
$16y^2+16y-1=0$
$(16y^2+16y-1=0)/16$
$y^2+y-1/16=0$
$y^2+y-1/16+1/4=1/4$
$(y+1/2)^2-1/16=1/4$
$(y+1/2)^2=5/16$
$\sqrt {(y+1/2)^2}=\sqrt {5/16}$
$y+1/2 =±\sqrt {5/16}$
$y=-1/2±\sqrt {5/16}$
