Answer
$x=-3/2 ±\sqrt {17/4}$
Work Step by Step
$4x^2+12x=8$
$4x^2+12x-8=0$
$(4x^2+12x-8=0)/4$
$x^2+3x-2=0$
$x^2+3x-2+17/4=17/4$
$x^2+3x+9/4=17/4$
$(x+3/2)^2=17/4$
$\sqrt{(x+3/2)^2}=\sqrt {17/4}$
$x+3/2 = \sqrt {17/4}$
$x=-3/2 ±\sqrt {17/4}$