Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.3 - Integrated Review - Summary on Solving Quadratic Equations - Page 791: 7

Answer

$x=-3/2 ±\sqrt {17/4}$

Work Step by Step

$4x^2+12x=8$ $4x^2+12x-8=0$ $(4x^2+12x-8=0)/4$ $x^2+3x-2=0$ $x^2+3x-2+17/4=17/4$ $x^2+3x+9/4=17/4$ $(x+3/2)^2=17/4$ $\sqrt{(x+3/2)^2}=\sqrt {17/4}$ $x+3/2 = \sqrt {17/4}$ $x=-3/2 ±\sqrt {17/4}$
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