Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.3 - Integrated Review - Summary on Solving Quadratic Equations - Page 791: 5

Answer

$x=-1±\sqrt {13}$

Work Step by Step

$x^2+2x-12=0$ $x^2+2x+1-1-12=0$ $(x+1)^2-13=0$ $(x+1)^2=13$ $\sqrt {(x+1)^2}=\sqrt {13}$ $x+1=\sqrt {13}$ $x=-1±\sqrt {13}$
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