Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.2 - Solving Quadratic Equations by Completing the Square - Exercise Set: 8

Answer

$y=-\dfrac{5}{2}\pm\dfrac{\sqrt{13}}{2}$

Work Step by Step

$y^{2}+5y+3=0$ Use the quadratic formula to solve this equation. The formula is $y=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$. For this equation $a=1$, $b=5$ and $c=3$ Substitute: $y=\dfrac{-5\pm\sqrt{5^{2}-4(1)(3)}}{2(1)}=\dfrac{-5\pm\sqrt{25-12}}{2}=...$ $...=\dfrac{-5\pm\sqrt{13}}{2}=-\dfrac{5}{2}\pm\dfrac{\sqrt{13}}{2}$
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