Answer
$m=1$ and $m=-6$
Work Step by Step
$m^{2}+5m-6=0$
Use the quadratic formula to solve this equation. The formula is $m=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$
In this equation, $a=1$, $b=5$ and $c=-6$
Substitute:
$m=\dfrac{-5\pm\sqrt{5^{2}-4(1)(-6)}}{2(1)}=\dfrac{-5\pm\sqrt{25+24}}{2}=...$
$...=\dfrac{-5\pm\sqrt{49}}{2}=\dfrac{-5\pm7}{2}$
Our two solutions are:
$m=\dfrac{-5+7}{2}=1$
$m=\dfrac{-5-7}{2}=-6$