Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Review: 59

Answer

$x_{1}=2$ and $x_{2}=-2$

Work Step by Step

Given $9y^2=36 , $ dividing by 9 both sides of the equation, we have: $9y^2=36 \longrightarrow y^2=4 \longrightarrow y^2-4=0$ Where $a=1,\ b=0,\ c=-4$ Using the quadratic formula: $\dfrac{-b\pm \sqrt{b^2-4ac}}{2a} , $ we have: $\dfrac{-0\pm \sqrt{0^2-4\times 1\times (-4)}}{2\times 1} = \dfrac{\pm \sqrt{16}}{2} = \pm \dfrac{ 4}{2} = \pm2$ Therefore the solutions are: $x_{1}=2$ and $x_{2}=-2$
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