Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Review - Page 832: 54

Answer

a) .4 seconds, 7.1 seconds b) All parabolas are symmetric across a line of symmetry. Since neither value for part A is the line of symmetry, that is why there are two answers for part A.

Work Step by Step

a) height of 350 feet $-16t^2+120t+300=350$ $-16t^2+120t+300-350=350-350$ $-16t^2+120t-50=0$ $a=-16$, $b=120$, $c=-50$ $x=(-b±\sqrt {b^2-4ac}) /2a$ $x=(-120±\sqrt {120^2-4*-16*-50}) /2*-16$ $x=(-120±\sqrt {14400-4*16*50}) /-32$ $x=(-120±\sqrt {14400-3200}) /-32$ $x=(-120±\sqrt {11200}) /-32$ $x=(-120±105.83) /-32$ $x=(-120-105.83) /-32$ $x=-225.83/-32$ $x=7.057$ $x=(-120+105.83) /-32$ $x=-14.17/-32$ $x=0.443$
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