Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Cumulative Review - Page 836: 34

Answer

$x=2$, $x=6$

Work Step by Step

$\sqrt {x-2} = \sqrt {4x+1} -3$ $(\sqrt {x-2})^2 = (\sqrt {4x+1} -3)^2$ $x-2 = (\sqrt {4x+1} -3)(\sqrt {4x+1} -3)$ $x-2= \sqrt {4x+1}*\sqrt{4x+1}+\sqrt {4x+1}*-3+\sqrt {4x+1}*-3=(-3)(-3)$ $x-2=4x+1-6\sqrt {4x+1}+9$ $x-2=4x+10-6\sqrt {4x+1}$ $x-2-4x-10=4x+10-6\sqrt {4x+1}-4x-10$ $-3x-12=-6\sqrt {4x+1}$ $(-3x-12)/-6=-6\sqrt {4x+1}/-6$ $.5x+2=\sqrt {4x+1}$ $(.5x+2)^2=(\sqrt {4x+1})^2$ $(.5x+2)^2=(4x+1)$ $(.5x+2)(.5x+2)=(4x+1)$ $.5x*.5x+2*.5x+2*.5x+2*2=4x+1$ $.25x^2+x+x+4=4x+1$ $.25x^2+2x+4=4x+1$ $.25x^2+2x+4-4x-1=4x+1-4x-1$ $.25x^2-2x+3=0$ $a=.25$, $b=-2$, $c=3$ $x=(-b±\sqrt {b^2-4ac})/2a$ $x=(-(-2)±\sqrt {(-2)^2-4*.25*3})/2*.25$ $x=(2±\sqrt {4-3})/.5$ $x=(2±\sqrt {1})/.5$ $x=(2±1)/.5$ $x=(2+1)/.5$ $x=3/.5$ $x=6$ $x=(2-1)/.5$ $x=1/.5$ $x=2$
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