## Algebra: A Combined Approach (4th Edition)

$7+24i$
$(4+3i)(4+3i)$ $4(4+3i)+3i(4+3i)$ $16+12i+12i+9i^{2}$ $16+24i+9i^{2}$ Since $i^{2}=-1$, the expression becomes $16+24i+9(-1)$ By solving, the expression reduces to $7+24i$