Answer
$x=6$
Work Step by Step
$\sqrt {x+5} = \sqrt {2x-1}$
$(\sqrt {x+5})^2 = (\sqrt {2x-1})^2$
$x+5=2x-1$
$5=x-1$
$6=x$
$\sqrt {x+5} = \sqrt {2x-1}$
$\sqrt {6+5} = \sqrt {2*6-1}$
$\sqrt {11} = \sqrt {12-1}$
$\sqrt {11} = \sqrt {11}$ (true)
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 10 - Test - Page 751: 24
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