Answer
$-1$
Work Step by Step
$i^{50}=i^{48}\times i^{2}=(i^{4})^{12}\times i^{2}$
As $i^{4}=1$ and $i^{2}=-1$,
$(i^{4})^{12}\times i^{2}=(1)^{12}\times (-1)=1\times-1=-1$.
Therefore, $i^{50}=-1$.
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 10 - Section 10.7 - Complex Numbers - Practice - Page 738: 20
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