Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.6 - Radical Equations and Problem Solving - Exercise Set - Page 729: 37

Answer

$x=9$

Work Step by Step

$\sqrt{x+4} =\sqrt {2x-5}$ $(\sqrt{x+4})^2 =(\sqrt {2x-5})^2$ $x+4=2x-5$ $x+9=2x$ $9=x$ $\sqrt{x+4} =\sqrt {2x-5}$ $\sqrt{9+4} =\sqrt {2*9-5}$ $\sqrt{13} =\sqrt {18-5}$ $\sqrt{13} =\sqrt {13}$ (true)
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