Answer
$\frac{6+3\sqrt x}{4-x}$
Work Step by Step
$\frac{3}{2-\sqrt x}\times\frac{2+\sqrt x}{2+\sqrt x}$
=$\frac{3(2+\sqrt x)}{(2-\sqrt x)(2+\sqrt x)}$
=$\frac{6+3\sqrt x}{(2)^{2}-(\sqrt x)^{2}}$
=$\frac{6+3\sqrt x}{4-x}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 10 - Section 10.5 - Rationalizing Numerators and Denominators of Radical Expressions - Practice - Page 715: 8
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