Answer
$\frac{6\sqrt 5-3}{19}$
Work Step by Step
$\frac{3}{2\sqrt 5+1}\times\frac{2\sqrt 5-1}{2\sqrt 5-1}$
=$\frac{3\times(2\sqrt 5-1)}{(2\sqrt 5+1)(2\sqrt 5-1)}$
=$\frac{6\sqrt 5-3}{(2\sqrt 5)^{2}-(1)^{2}}$
=$\frac{6\sqrt 5-3}{4(5)-1}$
=$\frac{6\sqrt 5-3}{20-1}$
=$\frac{6\sqrt 5-3}{19}$
