Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Integrated Review - Radicals and Rational Exponents: 39

Answer

$\frac{9y}{3\times\sqrt[3] (33y^{2})}$

Work Step by Step

$\sqrt[3] \frac{9y}{11}$ - Rationalize the numerator $\sqrt[3] \frac{9y}{11}\times\sqrt[3] \frac{9y}{9y}\times\sqrt[3] \frac{9y}{9y}$ - Multiply by these clever value of 1 to Rationalize top $\frac{9y}{\sqrt[3] (9\times9\times11\times(y)\times(y))}$ - simplify radicand $\frac{9y}{3\times\sqrt[3] (33y^{2})}$ - The numerator is rationalized
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