Answer
$-2y$
Work Step by Step
$\sqrt[5] {-32y^{5}}$
=$\sqrt[5] {-32\times y^{5}}$
=$\sqrt[5] {-32} \times \sqrt[5] {y^{5}}$
=$\sqrt[5] {(-2)^{5}} \times \sqrt[5] {y^{5}}$
=$-2\times y$
=$-2y$
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