Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set: 83

Answer

$\dfrac{-4+2\sqrt{3}}{6}=\dfrac{-2+\sqrt{3}}{3}$

Work Step by Step

$\dfrac{-4+2\sqrt{3}}{6}$ Take out common factor $2$ from the numerator and simplify: $\dfrac{-4+2\sqrt{3}}{6}=\dfrac{2(-2+\sqrt{3})}{6}=\dfrac{-2+\sqrt{3}}{3}$
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