Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set: 81

Answer

$\dfrac{6a^{2}b-9ab}{3ab}=2a-3$

Work Step by Step

$\dfrac{6a^{2}b-9ab}{3ab}$ Take out common factor $3ab$ from the numerator and simplify: $\dfrac{6a^{2}b-9ab}{3ab}=\dfrac{3ab(2a-3)}{3ab}=2a-3$
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