Answer
$(\sqrt{x-6}-7)^{2}=x-14\sqrt{x-6}+43$
Work Step by Step
$(\sqrt{x-6}-7)^{2}$
Use the formula for squaring a binomial to evaluate this product. The formula is $(a-b)^{2}=a^{2}-2ab+b^{2}$. In this expression, $a=\sqrt{x-6}$ and $b=7$
Substitute the known values into the formula and simplify if possible:
$(\sqrt{x-6}-7)^{2}=(\sqrt{x-6})^{2}-14\sqrt{x-6}+49=...$
$...=x-6-14\sqrt{x-6}+49=...$
$...=x-14\sqrt{x-6}+43$
