Answer
$(\sqrt{3}+x)^{2}=x^{2}+2x\sqrt{3}+3$
Work Step by Step
$(\sqrt{3}+x)^{2}$
Evaluate this power using the formula for squaring a binomial. The formula is $(a+b)^{2}=a^{2}+2ab+b^{2}$. In this expression $a=\sqrt{3}$ and $b=x$
Substitute the known values in the formula and simplify if possible:
$(\sqrt{3}+x)^{2}=(\sqrt{3})^{2}+2x\sqrt{3}+x^{2}=x^{2}+2x\sqrt{3}+3$
