## Algebra: A Combined Approach (4th Edition)

$\sqrt{\frac{9}{25}}=\frac{3}{5}, -\frac{3}{5}$
Since $(\frac{3}{5})^2=\frac{9}{25}$ and $(-\frac{3}{5})^2=\frac{9}{25}$ the square roots of $\frac{9}{25}$ are $\frac{3}{5},-\frac{3}{5}$