Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.1 - Radical Expressions and Radical Functions - Exercise Set: 10

Answer

$\sqrt{\frac{9}{25}}=\frac{3}{5}, -\frac{3}{5}$

Work Step by Step

Since $(\frac{3}{5})^2=\frac{9}{25}$ and $(-\frac{3}{5})^2=\frac{9}{25}$ the square roots of $\frac{9}{25}$ are $\frac{3}{5},-\frac{3}{5}$
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