Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Review: 152

Answer

$6\sqrt {5}-11x\sqrt[3] {5}$

Work Step by Step

$3\sqrt {20}-7x\sqrt[3] {40}+3\sqrt[3] {5x^{3}}$ =$3\sqrt {4\times5}-7x\sqrt[3] {8\times5}+3\sqrt[3] {5\times x^{3}}$ =$3\sqrt {2^{2}\times5}-7x\sqrt[3] {2^{3}\times5}+3\sqrt[3] {5\times x^{3}}$ =$3(2)\sqrt {5}-7x(2)\sqrt[3] {5}+3x\sqrt[3] {5}$ =$6\sqrt {5}-14x\sqrt[3] {5}+3x\sqrt[3] {5}$ =$6\sqrt {5}-11x\sqrt[3] {5}$
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