Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Review - Page 749: 147

Answer

$\frac{1}{8}$

Work Step by Step

$64^{-\frac{1}{2}}=(8^{2})^{-\frac{1}{2}}=(8)^{2\times-\frac{1}{2}}=8^{-1}=\frac{1}{8}$
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