Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Review - Page 749: 137

Answer

$-5-12i$

Work Step by Step

Step 1: $(2-3i)(2-3i)$ Step 2: $2(2-3i)-3i(2-3i)$ Step 3: $4-6i-6i+9i^{2}$ Step 4: $4-12i +9(-1)$ as $i^{2}=-1$ $4-9-12i$ $-5-12i$
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