## Algebra: A Combined Approach (4th Edition)

$1+5i$
$(3+2i)(1+i)$ $3(1+i)+2i(1+i)$ $3+3i+2i+2i^{2}$ $3+5i+2i^{2}$ Since $i^{2}=-1$, the expression becomes $3+5i+2(-1)$ Simplifying further, $3-2+5i$ Finally, $1+5i$