Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Review - Page 749: 130

Answer

$-\sqrt {10}$

Work Step by Step

$\sqrt {-2}\times\sqrt {-5}$ =$\sqrt {-1\times2}\times\sqrt {-1\times5}$ =$(\sqrt {-1}\times\sqrt {2})\times(\sqrt {-1}\times\sqrt {5})$ =$(i\times\sqrt {2})\times(i\times\sqrt {5})$ =$(i\sqrt {2})\times(i\sqrt {5})$ =$i\times i \times\sqrt 2\times\sqrt 5$ =$i^{2}\times\sqrt {2\times5}$ =$i^{2}\times\sqrt {10}$ =$(-1)\times\sqrt {10}$ =$-\sqrt {10}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.