Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Cumulative Review - Page 754: 39

Answer

$\frac{1}{8}$

Work Step by Step

$16^{-\frac{3}{4}}=\frac{1}{16^{\frac{3}{4}}}=\frac{1}{(2^{4})^{\frac{3}{4}}}=\frac{1}{(2)^{4\times\frac{3}{4}}}=\frac{1}{2^{3}}=\frac{1}{8}$
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