Answer
$3x+4$
Work Step by Step
$\dfrac{1}{2}(6x+7)+\dfrac{1}{2}$
$(\dfrac{1}{2})(6x)+(\dfrac{1}{2})(7)+\dfrac{1}{2}$
$(\dfrac{6}{2})x+(\dfrac{7}{2})+\dfrac{1}{2}$
$3x+(\dfrac{7}{2}+\dfrac{1}{2})$
$3x+(\dfrac{8}{2})$
$3x+4$
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