# Chapter 1 - Section 1.4 - Adding Real Numbers - Practice: 20

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#### Work Step by Step

We are asked to evaluate $x+3y$ for $x=-6$ and $y=2$. We can plug both values into the expression in order to evaluate. $(-6)+3(2)=-6+3\times2=-6+6=6+(-6)=6-6=0$

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