Answer
Please see the graph.
Work Step by Step
$g(x)= -1/2 * abs (x) -3$
Since the coefficient of the function is negative, the graph opens downward. We the vertex of the graph when $abs x$ is at its lowest point. Thus, at the vertex, $x=0$.
$x=0$
$g(x)= -1/2 * abs (x) -3$
$g(0)= -1/2 * abs (0) -3$
$g(0)=-1/2 *0 -3$
$g(0)=0-3$
$g(0)=-3$
The vertex is at $(0,-3)$. Since this point is below the x-axis, there are no x-intercepts.
